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Monday, 19 September 2011

Krankie No1 Handicap suggestion

Gerry,

This should simplify Al,s
say the winning score is 40
If you apply the following simple rules
where 1/gamma = (1 - v^2 / c^2)^(1/2) and is less than unity; here ^ means to the power of , so ^(1/2) means taking the square root. Since the value of c (= 3.00 x 10^8 m/s) is so large, length contraction is entirely negligible (e.g. 1 part in 2 x 10^12 for v = 1000 km/hr)
You easily arrive at me getting a extra 12 shots
Courtesy of my old mate Hawkins
Cheers
Krankie No. 1

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